Of course one cannot, but instead of giving you a collection of photographs that show different aspects of nature, I will share just this one photograph that seemed to me at the time to encapsulate the true beauty of nature as found in Britain. In this case in Wales, near Tywyn.
I took it when I was on my second holiday in the area when out on a walk.
This does include a universal pattern at the bottom as long as you don’t mind a bit of Maths!
Having had a few people interested in the possibility of a placemat in similar style to my Celtic Coaster, being the person I am, I wasn’t able to stop considering it.
My first thought was that it would be a lot of work and very fiddly. However……….
Imagining a placemat made in a similar way to the coaster as being made of similar width strips. I wondered how many that would need to be and in the end decided that about sixteen would equal a foot. (Not sure I am right here but it was a good place to start.)
Now the number of separate strips needed for a piece of Celtic plaitwork depends on the whether, on counting the number of bumps on each side (including the corners), the two numbers have a common factor.
No common factor: one piece (as in my odd numbered Celtic bookmarks.)
If there is a common factor that determines how many separate strips there are.
For a square, both sides are the same so you need that number of strips. Hence the style of my coasters.
I tend to think of placemats as being rectangular so having decided on sixteen colours for one foot (30cm). I chose to draw out one that was 16 x 32 bumps.
Now to be similar to my coasters each colour must be different. Sixteen was about the number of colours I used for my spectrum blanket so I coloured each strip in similar colours and produced this. Now one of the things I wanted with my coasters was for no adjacent overlaps to be the same colour.
I think, if you look closely, you will see that this breaks this rule in a vertical strip down the centre.
Of course a square placemat would not. (Each strip of the 16 x 32 placemat would need about 360 chains and there would be sixteen of them to weave together. That is a similar number of chains to those needed for each of my bookmarks.)
Now one person had asked about a matching coaster and obviously this could not match with all those colours so I looked to see what would happen if you repeated the colours of my first (non rainbow) coaster (As represented in my drawing programme) and got this. Even more matching adjacent overlaps.
Even if it was square. Some people might like the patterns it gives rise to but it wasn’t really what I wanted.
So I decided to work out how to make a bigger version of my coaster with the same shape strips but just wider.
As it was just a trial effort, I used some of my acrylic yarn that I had no specific plans for, as the cotton yarn is more expensive and I wasn’t sure I had enough anyway. Acrylic is much stretchier though and so needs more TLC to get it into shape. However I hope it will give you the general idea of what is possible.
For symmetry I decided to just make the strips three times wider and see how large it ended up. This would mean nine trebles (US-dcs) for each cross-over and over one hundred chains for each strip.
The thing that surprised me was to find that when adding further rows it takes two added rows to equal the width of one row on its own. So I ended up with five rows and not three! (And 114 starting chains see formula below.) Since each strip is approximately the same size you should need something less than 25g of each colour. As the whole thing weighed just under 85g. More of course if it was cotton. I used a 4.5mm hook for the starting chain and then a 4mm hook for the stitches. I tend to crochet quite tightly.
Here it is with a plate.
Although I was doing all this primarily for other people it has proved quite useful, as one of my first thoughts was to use plaitwork to make a cushion cover and now I have the tools to plan such a cover – watch this space!
For a square coaster, placemat etc.
If N is the number of bumps down the side (including the corners), N is also the number of strips and so also the number of colours needed if each strip is a different colour.
As an aside: I think that N is best if it is even, as if it is odd you get a square shape in the middle which I think stands out too much.
For an even number the first half of the shapes are the same as the second half and they blend together more. However the formula works for all values of N.
In all the following (US readers read ‘double crochet’ where I say ‘treble’)
Then for each strip if only one row wide:
The number of chains to start = 12(N-1) + 6. This includes the two extra chain needed for the first treble equivalent.
For thicker strips:
If m is the number of rows. I think m works best if it is odd from the point of view of symmetry. (If you chose an even numbered m you will have to adjust for any halves you get. I suggest rounding down as crochet is stretchy.)
The number of chains to start = 12[1 +(m-1)/2](N-1) + 6. This includes the two extra chain needed for the first treble equivalent.
Hope you remember your BODMAS!
I have even come up with a formula pattern for any size you might want to make.
For strips only one row wide:
Work the following, using values of ‘t’ from 1 to N.
(Following on from my remark about an even N, when N is even you can just make two each of the first N/2 shapes, which is what I did for the coaster.)
Treble into 4th chain from hook, 5tr into one chain,
Then one treble into each chain for 6(t-1) chains. (Yes this gives zero for the first ‘t’), 5trs into one chain.
Then one treble into each chain for 6(n-t) chains. 5trs into one chain.
Then one treble into each chain for 6(t-1) chains. 5trs into one chain.
Then one treble into each chain for 6(n-t)-2 chains. (This corrects for the first two trebles made at the beginning which will give a join that is underneath.)
A more general formula that will also work for thicker strips:
If N is the number of strips (colours) and m is the number of rows.
The first rows come from:-
Work the following, using values of ‘t’ from 1 to N-1. Then repeat t=1.
Treble into 4th chain from hook, Then one treble into each chain for [(m-1)/2] chains, 5tr into one chain,
Then one treble into each chain for 6(m+1)(t-1)/2 chains. (Yes this gives zero for the first ‘t’), 5trs into one chain.
Then one treble into each chain for 6(m+1)(n-t)/2 chains. 5trs into one chain.
Then one treble into each chain for 6(m+1)(t-1)/2 chains. 5trs into one chain.
Then one stitch into each chain for (6(m+1)(n-t)-(m+3))/2 chains. (This corrects for the extra trebles made at the beginning which will give a join that is underneath. If when you put the plait together the join is not underneath then you have the strip the wrong way up. I always presume that the right side is the front of the first row.)
For the rows after that work one tr into each tr except for the turns. (Remember to start with 3ch, miss the first stitch, and work the last tr into the top of the 3ch on the previous row.)
For 180deg turns, on the second row I worked into the 10 stitches of the turn as follows – (tr, tr, 2tr, 2tr, 2tr, 2tr, 2tr, 2tr, tr, tr) (16)
On the third row I worked into the central sixteen stitches of the above as follows – (tr, tr, tr, 2tr, tr, 2tr, tr, 2tr, 2tr, tr, 2tr, tr, 2tr, tr, tr, tr). (22)
Hopefully you can see a pattern here. I felt it was similar to working a circle, (or see below.)
For 90deg turns I simply worked 5trs into the central treble of the five of the previous row and one treble into all the others.
Pattern for 180deg turns continued
How the stitches increased for the fourth and fifth rows.
You may remember that I offered these three crosses as a Giveaway. Well sixteen people entered and I did the choosing today.
I know a lot of people use some sort of electronic chooser but I don’t quite trust things like that and like to do it the old fashioned way. However having put all the names on a list I did decide that it was easier to write numbers rather than names on slips of card. And the numbers I drew out showed that the winners were……….
Now 16 belonged to Patricia Lang and I am not sure if she wanted one but I had included her at the end just in case. I have sent her an email but not had a reply, so, rather than delay an announcement, I decided to draw another card and I will make Patricia one if she had meant to enter. So now the list is:-
I have sent each of you an email to request your postal address.
This year I made never-ending cards to send to the couple of people I send a card to, so I thought I would share one with you.
And to finish I will share with you the cake I made this Easter.
Not a simnel cake this year. My son saw a cake on a food programme on TV and really wanted to have one (and it also includes marzipan!) so I made one for him.And a closer look! A plain and chocolate Battenberg with nine sections instead of the normal four!
I couldn’t resist giving you a quick update on changes in the garden.
The wallflowers that I planted to keep the cats off the place where I am going to plant a daphne have come into flower and make a colourful show! The pansies that equally were planted to keep a spot for some lavender are flowering again though I can see the slugs are having a field day! The forget-me-nots that I love are flourishing.
The apple tree not only is coming into leaf but has blossom. I know I must not let the tree produce apples this year but I will enjoy the blossom.
And finally: the clematis that I showed you in an earlier post (taken last September)already has lots of new buds.
Always one to be pedantic. I looked up the definition of pond to see how it differed from that of a lake.
Google gave me this for pond:- “a small body of still water formed naturally or by artificial means.”
THIS gives a detailed explanation of the difference but basically it appears to be about depth rather than size.
So in order to be on the safe side I chose this picture that I took recently in London. This ornamental pond is in Victoria Embankment Gardens, the part next to Savoy Place, near the north end of Waterloo Bridge.
I also took a picture of this little chap that you can’t see in the above photograph because he is hidden by the tree fern.